The Reverse-order Law $(AB)^{\dag}=B^{\dag}(A^{\dag}ABB^{\dag})^{\dag}A^{\dag}$ and Its Equivalent EqualitiesTian · Kyoto journal of mathematics2005PDF128 KB
The Reverse Order Law\((ab)^\#=b^\dag (A^\dag Abb^\dag )^\Dag A^\dag \)in Rings with InvolutionMosić · Springer Milan2015PDF189 KB
