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What is UAM: Rolling Can Motion Analysis about?

Here are the steps to solve this problem: 1) We are given: Initial speed (vi) = 0 m/s Final speed (vf) = 20 m/s Displacement (Δx) = 150 m 2) Use the equation: vf2 = vi2 + 2aΔx 3) Plug in the values: 202 = 02 + 2a(150) 400 = 0 + 300a 400 = 300a a = 400/300 = 1.33 m/s2 So the acceleration of the train is 1.33 m/s2.

Author

Meya Jhana Navidad

Language

EN