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This document proves the formula 1 + 5 + 9 + ... + (4n − 3) = 2n2 − n through mathematical induction. It shows that the formula holds for n = 1, and assumes the formula is true for an arbitrary value k. Adding the next term [4(k + 1) − 3] results in the same formula but with k replaced with k + 1, proving the formula is true for all positive integers n.

Author

Scribdwiz

Language

EN