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Okay, here are the steps to solve this problem: (a) Given: Object distance (u) = 20 cm Focal length (f) = 8 cm Using the mirror equation: 1/u + 1/v = 1/f 1/20 + 1/v = 1/8 1/v = 1/8 - 1/20 1/v = 3/80 v = -40 cm Since the image distance (v) is negative, the image is virtual. (b) Magnification (M) = -v/u = -(-40)/20 = 2 So the magnification is 2. Since M > 1, the image

Author

Christopher Ndambo

Language

EN