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(c) at 0.25 FSD: Im = 0.25 × 0.1 mA = 0.025 mA Vm = Im Rm = 0.025 × 99 = 2.475 mV Vm 2.475 Is = = = 2.475 mA Rs 1 Total current: I = Is + Im = 2.475 + 0.025 = 2.5 mA So the total currents are: (a) 10 mA (b) 5 mA (c) 2.5 mA Determine the shunt resistance required to convert this PMMC into an ammeter with FSD of:
- Author
- ᗗᔡᙢᕱ ᘻᓎᖺᕢᙢᕦᖱ
- Language
- EN