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SOLVED EXAMPLE Ex.1 A north pole of strength 50 Am and south pole of strength 100 Am are separated by a distance of 10 cm in air. Find the force between them. Also find the force when the distance between them is doubled. Sol. Force between magnetic poles in air is given Given that m = 5 Am, 2? = 0.2 m,  = 30° and B = 15 Wbm–2   = MB sin  = (m × 2?) B sin  = 5 × 0.2 × 15 × 1 = 7.5 Nm. 2 by F = 0 × 4  m1 m2 r 2 Ex.4 A short magnet of length 4 cm is

Author

Raju Singh

Language

EN