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Material Balance in Reservoir Engineering by Idrissa Ba is a document available to read on EtoBox.
What is Material Balance in Reservoir Engineering about?
Np = 0.5 x 8 x 106 x (1.45 - 1.3) = 0.5 x 8 x 106 x 0.15 = 0.6 x 106 stb Given: N = 8 x 106 stb Boi = 1.3 rb/stb Bo = 1.45 rb/stb No water drive or gas cap (b) Same as (a) but includes water expansion term: Np = 0.5 x 8 x 106 x (1.45 - 1.3) + 0.3 x 8 x 106 x 3 x 10-6 x (3000 - 2500) = 0.6 x 106 + 0.12 x 106 = 0.72 x
- Author
- Idrissa Ba
- Language
- EN