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Boyle by Fezaret Jerome C. is a document available to read on EtoBox.

Here are the steps to solve problem 3: 1. Identify the given: V1 = 600 mL P1 = 760 torr V2 = 600 mL / 3 = 200 mL (volume is reduced by 1/3) 2. Derive the formula: P2 = P1V1/V2 3. Plug in the values: P2 = (760 torr) (600 mL) / 200 mL P2 = 228,000 torr / 200 mL P2 = 1,140 torr The pressure required to reduce the volume to 200 mL is 1,140 torr.

Author

Fezaret Jerome C.

Language

EN