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Here are the steps to solve this problem: 1. Column load = P = 1000 kN 2. Allowable net soil pressure = qall = 120 kPa 3. Footing A: P = 1000 kN qall = 120 kPa Required bearing area = P/qall = 1000/120 = 8.33 m^2 Width of footing A = ? Assuming depth = 1 m Width (B) = Required area/Depth = 8.33/1 = 2.5 m say 2.6 m 4. Footing B: Remaining load = 1000 - (2.6 x 120) = 1000 - 312 = 688 kN Required bearing

Author

Bosz' Ace

Language

EN