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This document provides an example problem demonstrating how to calculate the activation energy of a reaction from rate constants measured at different temperatures. The problem gives the rate constants for a second-order reaction at 3°C and 35°C. It then shows the steps to use the Arrhenius equation to calculate the activation energy, which is found to be 45.9 kJ/mol for this reaction. It also briefly discusses alternative methods for determining activation energy by plotting the rate constants versus tempe

Author

Saralin Nongbet

Language

EN