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JEE Advanced 2015 DPP #8 Solutions by Nibha Pandey is a document available to read on EtoBox.

1. The integrals A and B were evaluated to be 505π and 1004π respectively. 2. The integral I was evaluated to be 2000 - 615 = 1385. 3. The integral was evaluated to be ex(1+x)/(1-x). 4. The integral was evaluated to f(x) = x3sin2x + c. 5. It was concluded that the function f(x) is periodic with period 2. 6. The integral was evaluated by putting 2x6 + 3x4 + 6x2 = t. 7. It was shown that as n approaches infinity, the region is between -1 and 1 for both x and y.

Author

Nibha Pandey

Language

EN