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Okay, here are the steps to solve this problem: * Meter constant (K) = 400 rev/kWh (given) * Supply voltage (V) = 240 V * Load current (I) = 10 A * Power factor (PF) = 1 (not mentioned, assuming unity PF) * Power (P) = VI cosφ = 240 * 10 * 1 = 2400 W = 2.4 kW * Speed (N) = K * P = 400 rev/kWh * 2.4 kWh = 960 rev/hr Therefore, the speed of the meter disc for a current of 10 A is 960 revolutions per hour.

Author

Rushikesh wavare

Language

EN