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Energy Conversion in Power Plants by Patrick Mangapot Garcia is a document available to read on EtoBox.
* The generating station has an overall efficiency of 15% * 0.75 kg of coal is burnt per kWh of electricity generated * Let the calorific value of coal be C kcal/kg * Then energy input from burning 0.75 kg coal = 0.75C kcal * Energy output as electricity = 1 kWh = 860 kcal (given) * Using efficiency formula: Output energy/Input energy = Efficiency * 860 kcal / 0.75C kcal = 15% = 0.15 * 0.75C = 860/0.15 = 5733.33 kcal * C = 5733.33/0.75 = 7650
- Author
- Patrick Mangapot Garcia
- Language
- EN