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Given: Diameter of shaft (D) = 60 mm = 0.06 m Speed (N) = 180 rpm Permissible shear stress (τ) = 100 MPa = 100×106 N/m2 Torque (T) = (16τD3)/3 = (16×100×106×(0.06)3)/3 = 576×106 N-mm = 576 kN-mm Power (P) = 2πNT/60 = 2π×180×576×103/60 = 105 kW Therefore, torque = 576 kN-mm Power = 105 kW

Author

mike

Language

EN