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Problem06 01 by José Vieyra is a document available to read on EtoBox.
- Author
- José Vieyra
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- EN
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A force of 2.40 N acted over a distance of 1.5 m, doing 3.60 J of work. A force of -0.600 N acted over 1.5 m, doing -0.900 J of work. Subtracting the two amounts of work gives a total work of 2.70 J.
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