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Here are the steps to solve this problem: 1. By the handshake lemma, the sum of the degrees of all vertices is even. 2. Since the graph has 4 connected components, the degree sum must be accounted for within each component. 3. For a component to have an odd degree sum, it must have an odd number of vertices. 4. The smallest number of vertices a component could have to have an odd degree sum is 3. 5. But the total number of vertices in G is 15. If each component had 3 or fewer vertices, the total would be

Author

Dwi Maryono

Language

EN