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Ta is constant 5) Energy Balance: dT H R rA 0 dV 27 Heat Exchanger – Example Case 1 – Constant Ta Given: Ta = 300 K CA0 = 5 kmol/m3 ΔHR = -20,000 J/kmol Ua = 1000 W/m2-K E = 10,000 J/kmol T1 = 298 K ΔS = -20 J/kmol-K R = 8.314 J/kmol-K Determine: 1) Conversion
- Author
- Fachri Arief
- Language
- EN