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* Magnetite contains 95% Fe3O4 and 5% impurities * 1 ton of metallic iron requires: - 3.4 tons of Fe3O4 (since Fe3O4 produces 1 ton of Fe upon reduction with H2) - 3.4 * 0.05 = 0.17 tons of impurities * Therefore, the total quantity of magnetite required is: - Fe3O4 required = 3.4 tons - Impurities required = 0.17 tons - Total magnetite required = 3.4 + 0.17 = 3.57 tons Therefore, the quantity of magnetite containing 5% impurities required for the production of 1 ton of metallic iron is 3.

Author

Jojo Hany

Language

EN