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1. The problem seeks to maximize the objective function Z = 120X1 + 100X2 subject to two constraints: X1 + X2 ≤ 4 and 5X1 + 3X2 ≤ 15, with non-negativity conditions. 2. Graphically, the feasible region is bounded by the two constraints within the first quadrant. 3. The point (2,1) satisfies both constraints and lies within the feasible region, and is thus a feasible solution. 4. The point (3/2, 5/2) maximizes the objective function within the feasible region, and is therefore the optimal feasible solutio

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bnzayd2005

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EN