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* Let the other two zeros be a and b * Using Factor Theorem, we can write: f(x) = 2(x+2)(x+1)(x-a)(x-b) * Expanding the right hand side and comparing coefficients with the given polynomial f(x), we get: 2(x+2)(x+1)(x-a)(x-b) = 2x4 + x3 - 14x2 - 19x - 6 * Equating coefficients of x3 and x2, we get: a + b = 3 ab = 7 * Solving the above two equations, we get: a = 3, b = 1 Therefore

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