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I1 = I1’ + I0 cos φ0 = 21.714 + 5 cos 78.46 = 21.714 + 1.1 = 22.814A iii. Given: I2 = 200A, cos φ2 = 0·8; φ2 = cos–1 (0·8) = 36.87o Using: I1 = I1’ + I0 cos φ0 = I2 (N2/N1) + I0 cos φ0 22.814 = (200)(38/350) + 5 cos 78.46 22.814 = 21.714 + 1.1 Therefore, cos φ1 = I2(N2

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alex

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