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Interest Calculations and Sequences by effa86 is a document available to read on EtoBox.

Here are the steps to solve this problem: (a) (i) Distance in 3rd session = 3000 + 3 × 400 = 3800 m (ii) Distance in nth session = 3000 + (n - 1) × 400 (b) 42.195 = 3000 + (k - 1) × 400 42.195 - 3000 = 400(k - 1) 12.195 = 400(k - 1) k = 31 (c) Distance in 1st session = 3000 m Distance in 50th session = 3000 + 49 × 400 = 21000 m Total distance = 50 × (3000 + 49 × 400) / 1000 = 125 km (d) Distance

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effa86

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EN