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A 10.0 g sample of a 10.2 wt% solution of nickel sulfate hexahydrate contains 1.02 g of nickel sulfate hexahydrate. Since nickel sulfate hexahydrate is 262.85 g/mol and contains 1 mole of nickel per mole of compound, the 1.02 g of nickel sulfate hexahydrate contains 1.02/262.85 = 0.00388 moles of nickel. This is equivalent to 0.00388 * 58.6934 g/mol = 0.228 g of nickel.
- Author
- jeru2003
- Language
- EN