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What is Properties of Mixtures in Physical Chemistry about?

Here are the steps to solve this problem: 1) Molar masses: Mwater = 18 g/mol Methanol = 46.07 g/mol 2) Moles of each substance: nwater = masswater/Mwater = 50 g / 18 g/mol = 2.778 mol nethanol = massethanol/ Methanol = 50 g / 46.07 g/mol = 1.085 mol 3) Partial molar volumes at infinite dilution: Vwater = 18 cm3/mol Vethanol = 58 cm3/mol 4) Total volume using partial molar volumes: Vtotal = nwaterVwater + nethan

Author

Yahya Alhaddi KA201 18

Language

EN