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What is Estimation of Parameters in Statistics about?

Okay, here are the step-by-step workings: * Sample size (n) = 1,200 * Number of observations in Class A (pa) = 550 * pa = 550/1200 = 0.458 * 1 - pa = 1 - 0.458 = 0.542 * z0.995/2 = 2.576 (from normal distribution table) * 99% Confidence Interval = pa ± 2.576(√(pa(1-pa)/n)) = 0.458 ± 2.576(√(0.458×0.542/1200)) = 0.458 ± 0.022 = (0.436, 0.480) So

Author

JohnRoldGleyPanaligan

Language

EN