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Given: Ca(HCO3)2 = 25 mg/L Mg(HCO3)2 = 15 mg/L MgSO4 = 10 mg/L Temporary hardness due to Ca(HCO3)2 and Mg(HCO3)2 Ca(HCO3)2 = 25 mg/L x 100/162 = 15.4 mg/L as CaCO3 Mg(HCO3)2 = 15 mg/L x 100/146 = 10.3 mg/L as CaCO3 Temporary hardness = 15.4 + 10.3 = 25.7 mg/L or 25.7 ppm Permanent hardness due to MgSO4

Author

Xavier Hunter

Language

EN