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The Vernam cipher is robust to small deviations from randomness by Ryabko, Boris is a scholarly article available to read on EtoBox.
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The Vernam cipher (or one-time pad) has played an important rule in cryptography because it is a perfect secrecy system. For example, if an English text (presented in binary system) $X_1 X_2 ... $ is enciphered according to the formula $Z_i = (X_i + Y_i) \mod 2 $, where $Y_1 Y_2 ...$ is a key sequence generated by the Bernoulli source with equal probabilities of 0 and 1, anyone who knows $Z_1 Z_2 ... $ has no information about $X_1 X_2 ... $ without the knowledge of the key $Y_1 Y_2 ...$. (The best strategy is to guess $X_1 X_2 ... $ not paying attention to $Z_1 Z_2 ... $.) But what should one say about secrecy of an analogous method where the key sequence $Y_1 Y_2 ...$ is generated by the Bernoulli source with a small bias, say, $P(0) = 0.49, $ $ P(1) = 0.51$? To the best of our knowledge, there are no theoretical estimates for the secrecy of such a system, as well as for the general case where $X_1 X_2 ... $ (the plaintext) and key sequence are described by stationary ergodic processes. We consider the running-key ciphers where the plaintext and the key are generated by stationary ergodic sources and show how to estimate the secrecy of such systems. In particular, it is shown tha
- Author
- Ryabko, Boris
- Published
- 2013
- Language
- EN