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Here is a proof by mathematical induction that: ∑ (5k - 3) = 5n+1 - 3(n+1) k=1 Base case (n=1): LHS = 5 - 3 = 2 RHS = 51 - 3(1+1) = 2 Inductive step: Assume true for n = k ∑ (5k - 3) = 5k+1 - 3(k+1) Show true for n = k+1: LHS = ∑ (5k - 3) + (5(k+1) - 3) = 5k+1 - 3(k+1)

Author
maribel angana
Language
EN

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