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The document describes determining if a relation R is in 3NF and converting it if necessary based on a set of functional dependencies. For the relation R(P, Q, R, S, T, U, V, W, X, Y) with functional dependencies PQ → R, P → ST, Q → U, U → VW, and S → XY: - The candidate key is determined to be PQ - P → ST, Q → U, U → VW, and S → XY violate 3NF as the determining attributes are not superkeys and determined attributes are not prime - R is decomposed into 5 relations R1-R5 placing each functional dependen

Author

Shrutika Tayde

Language

EN